Wakulla County, Florida Demographics 2026
Demographic data: ACS 2020–2024 five-year estimates. Sources and methodology
Wakulla County, Florida has a population of 35,387, the 48th most populous county in Florida. The median household income is $81,895 and the median home value is $258,300. The poverty rate is 6.7%.
Wakulla County Quick Facts
How Wakulla County Changed
Change from the non-overlapping 2015–2019 ACS period to 2020–2024. Earlier dollar figures are adjusted to 2024 dollars; changes marked “no clear change” are within the combined 90% margins of error.
| Metric | 2015–2019 | 2020–2024 | Change |
|---|---|---|---|
| Population | 32,321 | 35,387 | +9.5% |
| Median household income | $75,578 | $81,895 | No clear change (+8.4%) |
| Median home value¹ | $177,222 | $258,300 | +45.7% |
| Median gross rent | $1,103 | $1,108 | No clear change (+0.5%) |
Median Household Income
Median Home Value
Economy & Housing
Household Income Distribution
Detailed income brackets
Employment
Housing Overview
People & Demographics
Age Distribution
Race & Ethnicity
- White: 76.7%
- Black: 13.7%
- Hispanic: 4.9%
- Asian: 0.4%
- Other: 0.5%
Diversity Index
A less diverse community where one racial or ethnic group represents a large majority.
State average: 65 | National average: 61
Education
Educational Attainment (Adults 25+)
- < HS: 11.6%
- HS Diploma: 36.9%
- Some College: 19.8%
- Associate's: 8.4%
- Bachelor's: 14.8%
- Graduate+: 8.5%
Cities & Places in Wakulla County
| City | Population | Median Income | Poverty | Home Value |
|---|---|---|---|---|
| Crawfordville | 5,732 | $82,656 | 4.7% | $255,500 |
| Panacea | 894 | $37,983 | 5.7% | $105,600 |
| Sopchoppy | 496 | $54,643 | 8.7% | $250,000 |
| St. Marks | 243 | $62,321 | 3.7% | $256,300 |
Explore Florida Rankings
Population Overview
Wakulla County is located in Florida with a total population of 35,387. It is the 48th most populous county out of 67 in Florida. The county encompasses 4 Census-designated places.
Age Demographics
The median age in Wakulla County is 42.3 years. This is about the same as the state median of 42.6 years.
Economy, Income & Housing
The median household income in Wakulla County is $81,895. This is 10% higher than the state median of $74,568. It is also 1% higher than the national median of $80,734. The poverty rate stands at 6.7%. This is 47% lower than the state poverty rate of 12.6%. The unemployment rate is 3.3%. This is 32% lower than the state rate of 4.8%. The median home value is $258,300. Housing costs are 28% lower than the state median of $359,000. The home-value-to-income ratio is 3.2x. 81.9% of occupied housing units are owner-occupied. This homeownership rate is 21% higher than the state average of 67.6%.
Race & Ethnicity
The largest racial or ethnic group in Wakulla County is White (non-Hispanic), making up 76.7% of the population. Black or African American residents account for 13.7%. The White (non-Hispanic) population is significantly higher than the state average (76.7% vs 50.4%). The Hispanic or Latino population (4.9%) is well below the state average of 27.4%. The Asian population (0.4%) is well below the state average of 2.9%.
Education
23.3% of residents aged 25 and older hold a bachelor's degree or higher. This is 32% lower than the state rate of 34.2%. Nationally, 35.7% of adults hold at least a bachelor's degree. The high school graduation rate (or equivalent) is 88.4%.
Data Sources & Methodology
All figures for Wakulla County come from the U.S. Census Bureau's American Community Survey (ACS) 2020–2024 5-Year Estimates, with comparisons drawn against Florida and national averages from the same dataset. See our methodology page for how each metric is defined, or data.census.gov for official tables with margins of error.
Frequently Asked Questions
What is the population of Wakulla County, Florida?
Wakulla County has a population of 35,387, making it the 48th most populous county in Florida.
What is the median income in Wakulla County?
The median household income in Wakulla County is $81,895 with a poverty rate of 6.7%.
How many cities are in Wakulla County, Florida?
Wakulla County contains 4 Census-designated places.